The time for half life period of a certain reaction `A to` Products A is `2.0 mol L^(-1)`, how much time does it take for its concentration to come from `0.50` to `0.25` mol `L^(-1)` if it is a zero order reaction?

Options

A. 1 h
B. 4 h
C. `0.5`h
D. `0.25`h

Answer

D

Explanation

d) For zero order of reaction.
`t_(1//2) = ([A_(0)])/(2k)` or `k=([A_(0)])/(2t_(1//2))`
`k=(2.0molL^(-1))/(2 xx 1hr)=1 molL^(-1)hr^(-1)`
For zero order reaction,
`t=([A]_(0)-[A])/(k)`
`((0.5-0.2s)mol L^(-1))/(1 mol L^(-1) hr^(-1))` = 0.25 hr.