the rate of a chemical reaction becomes double for every `10^(@)` rise in temperature. If the tempeature is raised by `50^(@)`C, the rate of reaction increases by about:

Options

A. 10 times
B. 24 times
C. 32 times
D. 64 times

Answer

C

Explanation

c) `("Rate at" 50^(@)C)/("Rate at" T_(1)^(@)C) = 2^(50/10) = 32` times.