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In the reaction, P+Q rarr R+S the time...

In the reaction, `P+Q rarr R+S`
the time taken for `75%` reaction of `P` is twice the time taken for `50%` reaction of `P`. The concentration of `Q` varies with reaction time as shown in the figure. The overall order of the reaction is

A

2

B

3

C

0

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
d) For P, if `t_(50%)`=x then `t_(75%)=2x`, So order with respect to P is 1. From the given graph, concentration of Q decreases linearly with time. So, rate with respect to Q remains constant. Hence, order of reaction with respect to Q is zero.
The rate law expressions:
`r=k[P]^(1)[Q]^(0)`
So, overall order is 1+0=1.
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