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A graph between log (x/m) and log p is s...

A graph between log (x/m) and log p is straight line at an angle of `45^(@)` with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

Text Solution

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According to Freundlich adsorption isotherm,
log (x/m) = log K + 1/n log p
1/n = tan `45^(@)` = 1 , p = 0.2 atm , log K = 0.3010.
log (x/m) = 0.3010-0.6990 = - 0.398
(x/m) = Antilog (- 0.398) = Antilog (T.062) = 0.4
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