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In the adsorption of acetic acid vapors ...

In the adsorption of acetic acid vapors by 1 g of charcoal, the following data was obtained :
`{:(x(cm^(3)),0.726,0.478),(p(cm of Hg),0.570,0.210):}`

Text Solution

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According to Freundlich adsorption istherm,
x/m = `Kp^(1//n)` , log x/m = log K + 1/n log p
Substituting the values of x, m and p in the rwo equetions,
log `(0.726)/(1)=log K 1//n log 0.570`
log ` (0.478)/(1)= log K + 1//n log 0.210`
Substract eqn. (ii) from eqn (i),
(log 0.726 - log 0.478) = 1/n (log 0.570- log 0.210) , log `(0.726)/(0.478)=1/nlog "(0.570)/(0.210)`
`0.181=1//n(0.434)or1//n = (0.181)/(0.434)=0.4170`
In order to calculate the value of K, subsitute the value of 1/n in eqn. (i),
log 0.726 = log K + 0.4170 log 0.570
(- 0.139) = log K = 0.4170 (-0.244)
log K = - 0.139 + 0.102 = - 0.037 = `bar(1).963`
K= Antilog `bar(1).963=0.9183.`
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