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For coagulating 200 mL of arsenious sulp...

For coagulating 200 mL of arsenious sulphide sol, 10 mL of 1M NaCl solution is required. Find out the flocculation volum of NaCl.

Text Solution

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10 mL of 1 M NaCl solution contain 10 milli-moles
Now, 200 mL of arsenious sulphide `(As_(2)S_(3))` require for coagulation NaCl = 10 milli-moles
100 mL of solution require for coagulation `NaCl=(10)/(100)xx1000=50` milli-moles
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