Plot of log against log P is a straight line inclined at an angle of `45^(@)`. When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )

Options

A. 1 g
B. 2 g
C. 3 g
D. 5 g.

Answer

D

Explanation

`x//m=KP^(1//n)=10.0(0.5)=5`
If m = 1g , then x=5g(given `1//n = tan theta =tan 45^(@)`=1)