Arrange the following in order of decreasing N - O bond length `NO_(2)^(-),NO_(2)^(-),NO_(3)^(-)`

Explanation

This is on account of the difference in the hybridistain states of the nitrogen atoms in the two ions.
`NO_(2)^(-) , H=1//2[5+0-0+1]=3 (sp^(2)` hybridisation)
`NO_(2)^(+) , H=1//2[5+0-1+0]=2` (sp hybridisation)