Home
Class 12
CHEMISTRY
IO(3)^(-)+I^(-)+H^(+) to...

`IO_(3)^(-)+I^(-)+H^(+) to`

Text Solution

AI Generated Solution

To solve the reaction \( IO_3^{-} + I^{-} + H^{+} \) and identify the products, we can follow these steps: ### Step 1: Identify the Reactants The reactants given are: - Iodate ion \( IO_3^{-} \) - Iodide ion \( I^{-} \) - Hydrogen ion \( H^{+} \) ...
Promotional Banner

Topper's Solved these Questions

  • THE P-BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise N.C.E.R.T. Exemplar Problems|27 Videos

  • THE P-BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise Multiple Choice Questions|10 Videos

  • THE P-BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise Problems For Practice|54 Videos

  • THE OXYGEN FAMILY

    DINESH PUBLICATION|Exercise PREPARATORY PACKAGE|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the mole coefficient of H^(+) in the balanced equation. IO_(3)^(-) +I^(-)+H^(+) overset(OH^(-))rarr I_(2)+H_(2)O .

The coefficients of I^(-), IO_(3)^(-) and H^(+) in the balanced redox reaction, I^(-) + IO_(3)^(-) + H^(+ )to I_(2) + H_(2)O^(-) , are respectively

NalO_(3) reacts with NaHSO_(3) according to eaquation Io_(3)^(-)+3HSO_(3)^(-)to I^(-)+3H^(+)3SO_(4)^(2-) The weight of NaHSO_(3) required to react with 100 mL of solution containing 0.58 gm of is :

A sample of raw material contain NaNO_(3) . It contains some NaIO_(3) also. The NaIO_(3) can be used as a source of iodine, produced in the following reactions: IO_(3)^(-)+HSO_(3)^(-) to I^(-)+SO_(4)^(-) ...................(1) I^(-)+IO_(3)^(-) to I_(2)+H_(2)O ............(2) One litre of sample solution containing 396 g NaIO_(3) is treated with stoichiometric quantity of NaHSO_(3) . Now a substantial amount of solution is added to reaction mixture to bring about the reaction (2).