Why is Bi(V) a stronger oxidant than Sb(V) ?

(a) Account for the following observations : (i) SF_(1) is easily hydrolysed whereas SF_(6) is not easily hydrolysed. (ii) Chlorine water is a powerful bleaching agent. (iii) Bi (V) is a stronger oxidising agent than Sb(V) (b) What happens when : (i) White phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO_(2). (ii) XeF_(6) undergoes partial hydrolysis. (Give the chemical equations involved).

(a) Draw the structures of the following : (i) PCl_(5) (s) (ii) SO_(3)^(2-) Explain the following observations : (i) Ammonia has a higher boiling point than phosphin. (ii) Helium does not form any chemical compound. (iii) Bi (V) is a stronger oxidising agent than Sb (V).

Why is NH_(3) a stronger base than PH_(3) ?

Account for the follwing : (i) Bi(v) is a stronger oxidizing agent then Sb(v). (ii) N-N single bond is weaker then P - P Single bond. (iii) Noble gases have very low boiling points.

Assertion : Fluorine is a stronger oxidizing agent than iodine. Reason : Fluorine has greater electronegativity than iodine.