Why is `SF_(4)` easily hydrolysed while the hydrolysis while the hydrolysis of `SF_(6)` is difficult ?

Why is SiCl_(4) readily hydrolysed but C Cl_(4) is resistant to hydrolysis?

Explain why SF_(4) is easily hydrolysed, whereas SF_(6) is resistant to hydrolysis ?

Why is SF_(6) kinetically inert ?

Explain the following situations : (i) In the structure of HNO_(3) molecule , the N-O bond (121 pm) is shorter than N-OH bond (140pm). (ii) SF_(4) is easily hydrolysed whereas SF_(6) is not easily hydrolysed. (iii) XeF_(2) has a straight linear structure and not a bent angular structure.

Account for the following : (i) NH_(3) is a stronger base than PH_(3) (ii) Sulphur has a greater tendency for catention than oxygen. (iii) Bond dissociation energy of F_(2) is less than that of Cl_(2) . (OR) Explain the following situations : (i) In the structure of HNO_(3) moleucle, the N-O bond (121 pm) is shorter than the N-OH bond (140 pm). (ii) SF_(4) is easily hydrolysed whereas SF_(6) is not easily hydrolysed. (iii) XeF_(2) has a straight linear structure and not a bent angular structure.

Give reasons for the following observations : Why SF_(4) undergoes hydrolysis but not SF_(6) ? Or SF_(6) is inert towards hydroysis. SF_(6) is much less reactive than SF_(4) . Or (i) SF_(4) is easily hydrolysed whereas SF_(6) is not easily hydrolysed. (ii) Sulpher exhibits greater tendency for calenation than selenium. (iii) Sulpher has a higher tendency for catenation than oxygen.

(a) Account for the following observations : (i) SF_(1) is easily hydrolysed whereas SF_(6) is not easily hydrolysed. (ii) Chlorine water is a powerful bleaching agent. (iii) Bi (V) is a stronger oxidising agent than Sb(V) (b) What happens when : (i) White phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO_(2). (ii) XeF_(6) undergoes partial hydrolysis. (Give the chemical equations involved).

The structrue of SF_(4) is

The structure of SF_(4) is