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The decreasing order of bond angles from...

The decreasing order of bond angles from `NH_(3) (107^(@))` to `SbH_(3)(91.3^(@))` down the group 15 elements is due to :

A

increasing bond pair : bond pair repulsion

B

increasing p-orbital character on `sp^(3)` orbital

C

decreasing lone pair- bond pair repulsion

D

decreasing electronegativity.

Text Solution

Verified by Experts

The correct Answer is:
B
Due to increasing size of central atom, s character in `sp^(3)` hybridisation decreases and corresponding p character increases.
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DINESH PUBLICATION-THE P-BLOCK ELEMENTS -JEE (Main) & Other Engineering
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  16. HNO(3) + P(2)O(5) to A +B 'A' is oxyacid of phosphorus and 'B' is an...

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