The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.
P and Q, respectively, are the sodium salts of

Options

A. hypochlorous and chloric acids
B. hypochlorous and chlorous acids
C. chloric acid and perchloric acids
D. chloric and hypochlorous acids.

Answer

A

Explanation

According to available data :
`2NaOH+Cl_(2) overset(("cold"))to 2NaCl+underset((P))(NaClO)`
`6NaOH+3Cl_(2) overset(("hot"))to 5NaCl+underset((Q))(NaClO_(3)) + 3H_(2)O`
NaClO is the salt of hypochlorous acid
`NaClO_(3)` is the salt of chloric acid.