The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.
R, S and T, respectively, are

Options

A. `SO_(2)Cl_(2), PCl_(5) " and " H_(3)PO_(4)`
B. `SO_(2)Cl_(2), PCl_(3) " and " H_(3)PO_(3)`
C. `SOCl_(2), PCl_(3) " and " H_(3)PO_(2)`
D. `SOCl_(2), PCl_(5) " and " H_(3)PO_(4)`

Answer

D

Explanation

`Cl_(2)+SO_(2) to underset((R )) (SO_(2))Cl_(2)`
`10SO_(2)Cl_(2)+P_(4) to underset((S))(4PCl_(5))+10SO_(2)`
`PCl_(5)+4H_(2)O to underset((T))(H_(3)PO_(4))+5HCl`