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The oxidation states of the most electro...

The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` are

A

0 and 1

B

`-2 " and" -1`

C

`-2 " and " 0`

D

`-2 " and " +1`

Text Solution

Verified by Experts

The correct Answer is:
B
`BaO_(2)+H_(2)SO_(4) to BaSoverset(-2)(O_(4)) +H_(2)overset(-1)(O_(2))`
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