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The geometry of H(2)S and its dipole mom...

The geometry of `H_(2)S` and its dipole moment are :

A

Angular and non-zero

B

Angular and zero

C

Linear and non-zero

D

Linear and zero

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The correct Answer is:
To determine the geometry and dipole moment of H₂S (hydrogen sulfide), we can follow these steps: ### Step 1: Determine the Valence Electrons - Sulfur (S) has 6 valence electrons. - Each hydrogen (H) has 1 valence electron, and there are 2 hydrogen atoms. - Total valence electrons = 6 (from S) + 2 (from 2 H) = 8 valence electrons. **Hint:** Count the valence electrons of the central atom and the surrounding atoms to find the total. ### Step 2: Determine the Hybridization - The formula to determine the hybridization is: \[ \text{Hybridization} = \frac{\text{Number of valence electrons}}{2} \] - Here, we have 8 valence electrons, so: \[ \text{Hybridization} = \frac{8}{2} = 4 \] - Since the hybridization number is 4, it indicates that the geometry is based on the tetrahedral arrangement. **Hint:** Use the total number of valence electrons to find the hybridization and infer the geometry. ### Step 3: Determine the Molecular Geometry - In H₂S, we have 2 hydrogen atoms bonded to the sulfur atom and 2 lone pairs of electrons on sulfur. - The presence of lone pairs affects the geometry. The tetrahedral arrangement will adjust to accommodate the lone pairs, resulting in a bent or angular shape. **Hint:** Consider the presence of lone pairs when determining the final molecular shape. ### Step 4: Determine the Dipole Moment - Sulfur is more electronegative than hydrogen, which means the S-H bonds are polar. - The dipole moments of the individual S-H bonds do not cancel out due to the bent shape of the molecule, leading to a net dipole moment. **Hint:** Analyze the electronegativity differences and molecular shape to determine if the dipole moments cancel or add up. ### Conclusion - The geometry of H₂S is **angular** (or bent). - The dipole moment is **non-zero** due to the polar bonds and molecular shape. Thus, the correct answer is: **Option 1: Angular and non-zero.**
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The geometry of H_2S and its dipole moment are:

The geometry of H_2 S and its moment are :

Polar covalent molecules exhibit dipole moment. Dipole moment is equal to the product of charge separation, q and the bond length d for the bond. Unit of dipole moment is Debye. One Debye is equal to 10^(-18) esu-cm. Dipole moment is a vector quantity. It has both magnitude and direction. Hence, dipole moment of a molecule depends upon the relative orientation of the bond dipoles, but not on the polarity of bonds alone. A symmetrical structure shows zero dipole moment. Thus, dipole moment helps to predict the geometry of a molecules. Dipole moment values can be used to disinguisd between cis- and trans- isomers, ortho-, meta - and para - forms of a substance, etc. The dipole moment value of H-X molecule is 1.2 Debye. If the internuclear distance between H-X is 0.8Å then the % ionic character in H-X molecules is :

Polar covalent molecules exhibit dipole moment. Dipole moment is equal to the product of charge separation , q and the bond length d for the bond. Unit of dipole moment is debye. One debye is equal to 10^(-18) esu cm. Dipole moments is a vector quantity. It has both magnitude and direction. Hence, dipole moment of a molecule depends upon the relative orientation of the bond dipoles, but not on the polarity of bonds alone. A symmetrical structure shows zero dipole moment. Thus, dipole moment helps to predict the geometry of a molecules. Dipole moment values can be distinguish between cis- and trans- isomers, ortho, meta and pare-forms of a substance, etc. Q. A diatomic molecule has a dipole moment of 1.2D. If the bond length is 1.0times10^(-8) cm, what fraction of charge does exist each atom?

Polar covalent molecules exhibit dipole moment. Dipole moment is equal to the product of charge separation , q and the bond length d for the bond. Unit of dipole moment is debye. One debye is equal to 10^(-18) esu cm. Dipole moments is a vector quantity. It has both magnitude and direction. Hence, dipole moment of a molecule depends upon the relative orientation of the bond dipoles, but not on the polarity of bonds alone. A symmetrical structure shows zero dipole moment. Thus, dipole moment helps to predict the geometry of a molecules. Dipole moment values can be distinguish between cis- and trans- isomers, ortho, meta and pare-forms of a substance, etc. Q. Arrange the following compounds in increasing order of dipole moments, toluene (I), o-dichlorobenzene (II), m-dichlorobenzene (III) and p-dichlorobenzene (IV) :

Chemical bonding between two atoms is necessarily associated with an electrical moment arising out of the difference in electroegativity of two atoms. This means that every bond carries with it an electrical moment called the ''bond moment''. The dipole moment of a molecule is really the vectorial sum of the individual bond moment present in it. To compute the dipole moment it is necessary to find out the values of various bond moment. In the following table, dipole moment of different bonds are as given. {:(,rarr,rarr,rarr),("Bond",H-C,C-Cl,C=0),("Bond moments",0.4 D,1.5 D,2.5 D):} The group moments of few groups as given {:("Group",NO_(2),OH,CN,CH_(3)),("Direction of dipole","Towards N","Towards O","Towards N","Away from "CH_(3)),("Dipole moment",4D,1.6D,3.8D,0.4D):} The bond angle in H_(2)S is 97^(@) and its dipole moment is 1.5 D. The S-H bond distance is 0.15 nm. Therefore, approximate percentrage ionic cjaracter pf S-H bond is (neglect the effect of dipole moment of lone pair on sulphur atom in H_(2)S ). (Given : [cos 97^(@)=-0.121 and sqrt(0.88)=0.94] )

H_(2)O has a net dipole moment while BeF_(2) has zero dipole moment because :

The molecule (s) that will have dipole moment is/are:

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