The hybridisatipon of atomic orbitals of nitrogen in `NO_(2)^(+),NO_(3)^(-)"and"NH_(4)^(+)` respectively are

Options

A. `sp, sp^(3) " and " sp^(2)` respectively
B. `sp, sp^(2) " and " sp^(3)` respectively
C. `sp^(2), sp " and " sp` respectively
D. `sp^(2), sp^(3) " and " sp` respectively.

Answer

B

Explanation

`NO_(2)^(+)` : Hybridisation `=(1)/(2)(5+0-1+0)=r(sp)`
`NO_(3)^(-)` : Hybridisation `=(1)/(2) (5+0-0+1)=3(sp^(2))`
`NH_(4)^(+)` : Hybridisation `=(1)/(2)(5+4-1+0)=4 (sp^(3))`