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One mole of H3PO3 on reaction with exces...

One mole of `H_3PO_3` on reaction with excess of `NaOH` gives :

A

one mole of `Na_(2)HPO_(3)`

B

two moles of `Na_(2)H_(2)PO_(3)`

C

two moles of `Na_(2)HPO_(3)`

D

one mole of `Na_(3)PO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(3)PO_(3)` is a dibasic acid and reacts with excess of NaOH as :
`underset((1"mole"))(H_(3)PO_(3))+2NaOH to underset((1"mole"))(Na_(2)HPO_(3))+2H_(2)O`
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