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Why is Cr^(2+) reducing and Mn^(3+) oxid...

Why is `Cr^(2+)` reducing and `Mn^(3+)` oxidising when both have `d^4` configuration?

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`Mn^(3+)` is a strongest oxidising agne because after accepting an electron from the reducing agent, it acquires `Mn^(2+)` configuration which is quite stable.
`underset((3d^(4)))(Mn^(3+))(aq)+e^(-) to underset((3d^(5)))(Mn^(2+))(aq)`
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(a) What happens when (i) Manganate ions (MnO_(4)^(2-)) undergoes diSQProportionation reaction in acidic medium ? (ii) Lanthanum is heated with Sulphur? (b) Explain the following trends in the properties of the members of the First series of transition elements: (i) E^(@) (M^(2+)//M) value for copper is positive (+ 0.34 V) in contrast to the other members of the series. (ii) Cr^(2+) is reducing while Mn^(3+) is oxidising, though both have d^(4) configuration. (iii) The oxidising power in the series increases in the order VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_94)^(-) .

Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

The ion Cr^(2+) is redusing agent while that of Mn^(3+) is an oxidising agent though both have 3d^(4) configuration. This is because

Assertion :- Cr^(+2) is a reducing agent and Mn^(+3) is oxidising agent. Reason :- Mn^(+3) has d^(5) configuration.

How would you account for the following: (i) Cr^(2+) is reducing in nature while with the same d-orbital configuration (d^(4)) Mn^(3+) is an oxidising agent (ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation state occurs in the middle of the series.

How would you account for the following : (i) Cr^(2+) is reducing in nature while with the same d-orbital configuration (d^(4)),Mn^(2+) is oxidising in nature. (ii) In the transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series.

DINESH PUBLICATION-D-AND -F BLOCK ELEMENTS-Question From Board Examination
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  2. Why is enthalpy of atomisation is the lowest for Zn in 3d series of tr...

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  3. Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^4 confi...

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  5. Why do actinoid elements show wide range of oxidation states ?

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  11. Explain the following properties of transition elements. (i) Variab...

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  14. Complete the following : 3MnO(4)^(2-)+4H^(+) to

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  15. How will you account for the following : (a) (i) The chemistry of act...

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  17. (i) Account for the fact that Eu^(2+) is a strong reducing agent. (...

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  18. {:(E(M^(2+)//M)^(@),Cr,Mn, Fe, Co, Ni, Cu),(,-0.91,-1.18,-0.44,-0.28,-...

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  19. When chromite ore FeCr(2)O(4) is fuse with NaOH in presence of air, a ...

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