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How would you prepare (i) K(2)MnO(4) ...

How would you prepare
(i) `K_(2)MnO_(4)` and `MnO_(2)`? (ii) `Na_(2)Cr_(2)O_(7)` from `Na_(2)CrO_(4)` ?

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How do you prepare : (i) k_(2)MnO_(4) from MnO_(2) ? (ii) Na_(2)Cr_(2)O_(7) from NaCrO_(4) ? (b) Account for the following : (i) Mn^(2+) is more stable then Fe^(2+) towards oxidation to + 3 state. (ii) The enthelpy of atomization is lowest for Zn in 3d series of the transition elements. (iii) Actinoid elements show wide range of oxidation states.

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

FeCr_(2)O_(4)+Na_(2)CO_(3)+O_(2) to Fe_(2)O_(3)darr+Na_(2)CrO_(4)

Potassium dichromate (K_(2)Cr_(2)O_(7)) is an orange coloured compound , very frequently used in laboratory as an oxidising agent as well as in a redox titration. It is generally prepared from chromite (FeCr_(2)O_(4)) ore according to the following reactions: (1) Fusion of chromite ore with sodium carbonate in excess of air. FeCr_(2)O_(4) + Na_(2)CO_(3) + O_(2) rarr Na_(2)CrO_(4)+Fe_(2)O_(3) +CO_(2) (2) Acidifing filtered sodium chromate solution with sulphuric acid. Na_(2)CrO_(4) + H_(2)SO_(4) rarr Na_(2)Cr_(2)O_(7) + Na_(2)SO_(4) + H_(2)O (3) Treating sodium dichormate with potassium choride . Na_(2)Cr_(2)O_(7) + KCl rarr K_(2)Cr_(2)O_(7) + NaCl If the number of moles of reactant available for reaction are : [FeCr_(2)O_(4)=0.25 "moles" , O_(2)=0.35 "moles", Na_(2)CO_(3)=0.60 "moles", H_(2)SO_(4)=0.2 "moles", KCl=0.4 "moles"] , then the maximum number of moles of K_(2)Cr_(2)O_(7) , that can be produced is :