Among the transition metals of 3d series, that one that has the highest negative `M^(2+)//M` standard electrode potential is

Options

A. Ti
B. Cu
C. Mn
D. Ni

Explanation

To determine which transition metal from the 3d series has the highest negative \( M^{2+}/M \) standard electrode potential, we can follow these steps:

### Step 1: Identify the Transition Metals in the 3d Series
The 3d series of transition metals includes the following elements:
- Scandium (Sc)
- Titanium (Ti)
- Vanadium (V)
- Chromium (Cr)
- Manganese (Mn)
- Iron (Fe)
- Cobalt (Co)
- Nickel (Ni)
- Copper (Cu)
- Zinc (Zn)

### Step 2: Look Up Standard Electrode Potentials
We need to find the standard electrode potentials for the \( M^{2+}/M \) half-reactions of these metals. The relevant standard electrode potentials (in volts) for the metals mentioned in the video are:
- Titanium (Ti): \( -1.63 \, \text{V} \)
- Manganese (Mn): \( -1.18 \, \text{V} \)
- Nickel (Ni): \( -0.24 \, \text{V} \)
- Copper (Cu): \( +0.34 \, \text{V} \)

### Step 3: Compare the Values
Now we compare the standard electrode potentials:
- Titanium: \( -1.63 \, \text{V} \)
- Manganese: \( -1.18 \, \text{V} \)
- Nickel: \( -0.24 \, \text{V} \)
- Copper: \( +0.34 \, \text{V} \)

Among these values, the most negative electrode potential is that of titanium, which is \( -1.63 \, \text{V} \).

### Step 4: Conclusion
Therefore, the transition metal from the 3d series that has the highest negative \( M^{2+}/M \) standard electrode potential is **Titanium (Ti)**.

### Final Answer:
**Titanium (Ti)** has the highest negative \( M^{2+}/M \) standard electrode potential among the 3d transition metals.

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