The atomic number of V,Cr, Mn and Fe are...

The atomic number of `V,Cr, Mn and Fe` are respectively `23,24,25 and 26.` Which one of these may be expected to have the highest second ionization enthalpy?

A

Cr

B

Mn

C

Fe

D

V

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The correct Answer is:

A

`Cr(3d^(5)4s^(1))` is expected to have highest value of second ionsiation enthalpy.

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