Home
Class 12
CHEMISTRY
Which of the following statement are cor...

Which of the following statement are correct about `Cr^(2+)` (Z = 24) and `Mn^(3+)` (Z = 25) ?
(i) `Cr^(2+)` is a reducing agent
(ii) `Mn^(3+)` is an oxidizing agent
(iii) Both `Cr^(2+)` and `Mn^(3+)` exhibit `d^(4)` configuration
(iv) When `Cr^(2+)` is used as a reducing agent, the chromium ion attains `d^(5)` electronic configuration

A

`Cr^(2+)` is a reducing agent

B

`Mn^(3+)` is an oxidising agent

C

Both `Cr^(2+)" and "Mn^(3+)` exhibit `d^(4)` electronic configuration

D

When `Cr^(2+)` is used as a reducing agent, chromium ion attains `d^(5)` electronic configuration.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
(a,b,c) are correct statements.
(a) In aqueons solution, `Cr^(2+)" "(3d^(4))` acts as a reducing agent and gets oxidised to `Cr^(3+)" "(3d^(beta))` which gives half filled `t_(2g)` level in the octahedral ligand filed of `H_(2)O`.
(b) `Mn^(3+)" "(3d^(4))` acts as an oxidising agent and is reduced to `Mn^(2+)" "(3d^(5))` which has stable electronic configuration.
(c) Both `Cr^(2+)" and "Mn^(3+)` ions have `d^(4)` electronic configuration.
(d) It is a wrong statement. Upon oxidation, `Cr^(2+)" changes to "Cr^(3+)` and not to `Cr^(5+)`.
Promotional Banner

Topper's Solved these Questions

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise ASSERTION-REASON TYPE QUESTIONS|23 Videos

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise INTEGER ANSWER TYPE QUESTIONS|15 Videos

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise STRAIGHT OBJECTIVE TYPE MCQS (SINGLE CORRECT OPTION)|16 Videos

  • CYANIDES, ISOCYANIDES, NITROCOMPOUNDS AND AMINES

    DINESH PUBLICATION|Exercise Unit test - 8|20 Videos

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise ADDITIONAL NUMERICAL PROBLEMS FOR PRACTICE|12 Videos

Similar Questions

Explore conceptually related problems

Assertion :- Cr^(+2) is a reducing agent and Mn^(+3) is oxidising agent. Reason :- Mn^(+3) has d^(5) configuration.

Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

The ion Cr^(2+) is redusing agent while that of Mn^(3+) is an oxidising agent though both have 3d^(4) configuration. This is because

With 3d^(4) configuration, Cr^(2+) acts as a reducing agent but Mn^(3+) acts as an oxidising agent. Explain.

Four statement of Cr and Mn are given below. (P). Cr^(2+) and Mn^(3+) have the same electronic configuration. (Q). Cr^(2+) is a reducing agent while Mn^(3+) in an oxidizing agent. (S). Both Cr and Mn are oxidizing agent. The correct statement are:

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Which of the following is true for the species having 3d^(4) configuration? (A) Cr^(2+) is reducing in nature. (B) Mn^(3+) is oxidising in nature. (C) Both (A) and (B) (D) None of these