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The number of moles of K(2)Cr(2)O(7) red...

The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions is

A

`1//3`

B

3

C

`1//4`

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `Cr_(2)O_(7)^(2-)+3Sn^(2+)+14H^(+)rarr2Cr^(3+)+3Sn^(4+)+7H_(2)O`
3 moles of `Sn^(2+)` ions are oxidised by `Cr_(2)O_(7)^(2-)` ions =1 mole.
1 mole of `Sn^(2+)` ions are oxidised by `Cr_(2)O_(7)^(2-)` ions = `1//3` mole.
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