How does `K_(2)[PtCl_(4)]` get ionised when dissolved in water ? Will it form precipitate when `AgNO_(3)` solution is added to it ? Give reason for your answer ?

Explanation

It will ionises as follows :
`K_(2)[PtCl_(4)] implies 2K^(+) + [PtCl_(4)]^(2-)`
no precipitate will be formed because the `Cl^(-)` ions are oresent in the co-ordination sphere and will not react with `Ag^(+)` ions .