A metal ion `M^(n+)` HAVING `D^(4)` valence electronic configuration combines with three bidentate ligands to form a complex compound . Assuming `Delta_(0) gt P` :
(i) write the electronic configuration of `d^(4)` ion .
(ii) what type of hybridisation will `M^(n+)` ion has ?
(iii) Nmae the type of isomerism exhibited by this complex .

Explanation

To solve the problem step by step, we will address each part of the question systematically.

### Step 1: Write the electronic configuration of `d^(4)` ion.

The `d^(4)` configuration means that there are 4 electrons in the d-orbitals. Given that the complex is formed in an octahedral field and assuming that `Δ₀ > P` (where `Δ₀` is the crystal field splitting energy and `P` is the pairing energy), the electrons will fill according to the crystal field theory.

In an octahedral field:
- The d-orbitals split into two sets: the lower energy t₂g (three orbitals) and the higher energy eₖg (two orbitals).
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