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The oxidation state of Cr in [Cr(NH(3))(...

The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:

A

`+2`

B

`+3`

C

`+4`

D

`+5`

Text Solution

Verified by Experts

The correct Answer is:
A
`[Cr(NH_3)_4Cl_2]^(+)`
x + 4(0) + 2(-1) + +1
x = +1 + 2 = +3
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