`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.

Options

A. `3d_(xy)^(1) , 3d_(yz)^(1) , 3d_(xz)^(1)`
B. `3d_(xy)^(1) , 3d_(yz)^(1) , 3d_(z^(2))^(1)`
C. `3d_(x^(2) - y^(2))^(1) , 3d_(z^(2))^(1) , 3d_(xz)^(1)`
D. `3d_(xy)^(1) , 3dx^(2) - y^(2) , 3d_(yz)^(1)`

Answer

A

Explanation

a) Since the magnetic moment`(mu)` = 3.83 BM, the numbe of unpaired ios 3.
`sqrt(n(n+2)) = 3.83` or `n(n+2) = (3.83)^(2) = 15`
this means that n=3
`d^(2)sp^(3)` hybridisation