`int_3^6x y dx=9sqrt(3),w h e nx=6costheta, y=2sintheta`

If x=2costheta , y=3sintheta Find dy/dx .

Find dy/dx if x=2sintheta , y=3costheta

Eliminate theta,if x=2 costheta-3sintheta y= costheta+2sintheta

If x=2costheta , y=3sintheta Find (d^2y)/(dx^2) .

int (6x^(2)dx)/(sqrt(9-x^(3))) =

theta is acute angle between the lines x^(2)-xy-6y^(2)=0 , then (2costheta+3sintheta)/(4sintheta+5costheta) is

If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1+sintheta) is equal to

If x+cos^(3)theta=3costheta,y+sin^(3)theta=3sintheta," then "(dy)/(dx)=

Eliminate theta in the following (i) 2sintheta=x, 3costheta=y (ii) costheta + sintheta=x, costheta-sintheta=y