Home
Class 11
MATHS
Find the equation of the circle which cu...

Find the equation of the circle which cuts the three circles `x^2+y^2-3x-6y+14=0,x^2+y^2-x-4y+8=0,` and `x^2+y^2+2x-6y+9=0` orthogonally.

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

The equation of the circle which cuts the three circles x^(2)+y^(2)-4x-6y+4=0 , x^(2)+y^(2)-2x-8y+4=0 and x^(2)+y^(2)-6x-6y+4=0 orthogonally is

The equation of a circle which cuts the three circles x^(2)+y^(2)+2x+4y+1=0,x^(2)+y^(2)-x-4y+8=0 and x^(2)+y^(2)+2x-6y+9=0 orthogonlly is

Find the equation of the circle which cuts the circles x^2+y^2+4x+2y+1=0, 2(x^2+y^2)+8x+6y-3=0 and x^2+y^2+6x-2y-3=0 orthogonally.

Find the equation of the circle which cuts the circles x^2+y^2+4x+2y+1=0, 2(x^2+y^2)+8x+6y-3=0 and x^2+y^2+6x-2y-3=0 orthogonally.

The equation of the tangent at the point (0,3) on the circle which cuts the circles x^2 +y^2-2x+6y=0 , x^2 +y^2-4x-2y+6=0 and x^2 +y^2-12x+2y+3=0 orthogonally is

The length of the diameter of the circle which cuts three circles : x^2+y^2-x-y-14=0 x^2+y^2+3x-5y- 10=0 x^2+y^2-2x+3y-27=0 orthogonally, is :

Find the equation of the circle which cuts the circles x^2+y^2-4x-6y+11=0 and x^2+y^2-10x-4y+21=0 orthogonally and has the diameter along the line 2x+3y=7.