Equation of plane (vector and cartesian form) in point normal form

The foot of the perpendicular drawn from the origin O to a plane is N(12,-4,-3). Find the equation of the plane in cartesian form and vector form.

Equation of plane in normal form

Equation of normal in Point form

The foot of the perpendicular drawn from the origin 0 to a plane is N(12,-4,-3). Find the equaion of the plane in cartesian form and vector form.

The equation of the plane in cartesian form, which is at a distance of (6)/(sqrt(29)) from the origin and its normal vector drawn from the origin being 2 hat(i)-3hat(j)+4hat(k) , is

Find the equation of plane in Cartesian form which is at a distance of 5 unit from origin and its normal vector from origin is parallel to a vector formed by joining points A(1, 2, 3) and B(3, -4, -6).

Find the equation of plane in Cartesian form which is at a distance of 5 unit from origin and its normal vector from origin is parallel to a vector formed by joining points A(1, 2, 3) and B(3, -4, -6).

The foot of the perpendicular from the origin to a plane is P(4,-2,5). Write bar(OP) Find the equation of the plane in vector and Cartesian form.

Find the equation of plane in Cartesian form which is at a distance 3/sqrt(41) from origin and its normal vector from origin is 3hati-4hatj-4hatk