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Prove that (log)7 10 is greater than ...

Prove that `(log)_7 10` is greater than `(log)_(11)13.`

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The number N=(1+2log_(3)2)/((1+log_(3)2)^(2))+log_(6)^(2)2 when simplified reduces to: a prime number an irrational number a real which is less than log_(3)pi a real which is greater than log _(7)6

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than (1) 1/((log)_(10)^4-(log)_(10)^3) (2) 1/((log)_(10)^4+(log)_(10)^3) (3) 9/((log)_(10)^4-(log)_(10)^3) (4) 4/((log)_(10)^4-(log)_(10)^3)