If `f(x)={x^nsin(1/(x^2)),x!=0 0,x=0,(n in I),t h e n` `("lim")_(xvec0)f(x)e xi s t sforn >1` `("lim")_(xvec0)f(x)e xi s t sforn<0` `("lim")_(xvec0)f(x)` does not exist for any value of `n` `("lim")_(xvec0)f(x)` cannot be determined

If f(x)={(x^nsin(1/(x^2)),x!=0), (0,x=0):}, (n in I), then (a) lim_(xrarr0)f(x) exists for n >1 (b) lim_(xrarr0)f(x) exists for n<0 (c) lim_(xrarr0)f(x) does not exist for any value of n (d) lim_(xrarr0)f(x) cannot be determined

If f(x)={x-1,xgeq1 2x^2-2,x 0-x^2+1,xlt=0,a n dh(x) =|x|,t h e n("lim")_(xvec0)f(g(h(x))) is___

If f(x)=(3x^2+a x+a+1)/(x^2+x-2), then which of the following can be correct ("lim")_(xvec1)f(x)e xi s t s a=-2 ("lim")_(xvec-2)f(x)e xi s t s a=13 ("lim")_(xvec1)f(x)=4/3 ("lim")_(xvec-2)f(x)=-1/3

if f(x)=e^(-(1)/(x^(2))),x>0 and f(x)=0,x<=0 then f(x) is

f(x)=e^x then lim_(x rarr 0) f(f(x))^(1/{f(x)} is

If [.] is the greatest integer function and f(x)=[tan^2x], then (a) ("lim")_(xvec0)f(x) does not exist (b) f(x) is continuous at x=0 (c) f(x) is not differentiable at x=0 (d) f^(prime)(0)=1

If f(x)={("sin"[x])/([x]),for[x]!=0 0,for[x]=0,w h e r e[x] denotes the greatest integer less than or equal to x , then ("lim")_(xvec0)f(x) is 1 (b) 0 (c) -1 (d) none of these

Let f(x)={cos[x],xgeq0|x|+a ,x<0 The find the value of a , so that ("lim")_(xvec0) f(x) exists, where [x] denotes the greatest integer function less than or equal to x .

If f(x)={x/(s in x),x >0 2-x ,xlt=0 and g(x)={x+3,x<1x^2-2x-2,1lt=x<2x-5,xgeq2 Then the value of (lim)_(xvec0)g(f(x)) a. is -2 b. is -3 c. is 1 d. does not exist

Column I ([.] denotes the greatest integer function), Column II ""("lim")_(xvec0)([100(sinx)/x]+[100(tanx)/x]) , p. 198 ("lim")_(xvec0)([100 x/(sinx)]+[100(tanx)/x]) , q. 199 ("lim")_(xvec0)([100(sin^(-1)x)/x]+[100(tan^(-1)x)/x]) , r. 200 ("lim")_(xvec0)([100 x/(sin^(-1)x)]+[100(tan^(-1)x)/x]) , s. 201