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Let f(x)=-ax^2-b|x|-c, -alpha le x lt 0,...

Let `f(x)=-ax^2-b|x|-c, -alpha le x lt 0, ax^2+b|x|+c 0 le x le alpha` where a,b,c are positive and `alpha gt 0`, then- Statement-1 : The equation f(x)=0has atleast one real root for `x in [-alpha,alpha]` Statement-2: Values of `f(-alpha) and f(alpha)` are opposite in sign.

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