If `z=x+iy,` then the equation `|(2z-i)/(z+1)|=k` will be a straight line, where -

If z=x+iy , then the equation |z+1|=|z-1| represents

If z=x+iy then the equation of a straight line A x+B y+C=0 where A ,B ,C in R , can be written on the complex plane in the form a z+a z +2C=0 where ' a ' is equal to ((A+i B))/2 (b) (A-i B)/2 A+i B (d) None of these

Solve the equation z^(2)=bar(z) where z=x+iy

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

The complex plane of z=x+iy , which satisfies the equation |(z-5i)/(z+5i)|=1 , lies on

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+i)))=m represents a circle, then m can be