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(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alph...

(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alpha)/(tan2 alpha)

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Prove that, (sec 8 alpha -1)/(sec 4 alpha-1)= (tan 8 alpha)/(tan 2 alpha

If alpha_(1),alpha_(2),alpha_(3),...,alpha_(n) are in A.P whose common common difference is d then sin d[sec alpha_(1)sec alpha_(2)+sec alpha_(2)sec alpha_(3)+...+sec alpha_(n-1)sec alpha_(n)]=tan alpha_(n)-tan alpha_(1)

(1)/(sec alpha - tan alpha ) - (1)/( cos alpha)=

If sec alpha=(5)/(4), evaluate (1-tan alpha)/(1+tan alpha)

If alpha_1 , alpha_2, ......, alpha_n are in A.P, whose common difference is d , show that sin d [ sec alpha_1 sec alpha_2 + sec alpha_2 sec alpha_3 +.......+ sec alpha_(n - 1) sec alpha_n] = tan alpha_n - tan alpha_1

Prove the following Identity: (tan alpha+sec alpha-1)/(tan alpha-sec alpha+1)=(1+sin alpha)/(cos alpha)

The value of (cot^(2)alpha)((sec alpha-1)/(1+sin alpha))+sec^(2)alpha((sin alpha-1)/(1+sec alpha)) is

(1+sin alpha)/(1+cos alpha)*(1+sec alpha)/(1+cos ec alpha)=tan alpha