fn(x)=e^(f(n-1)(x)) for all n in Na n ...

`f_n(x)=e^(f_(n-1)(x))` for all `n in Na n df_0(x)=x ,t h e n d/(dx){f_n(x)}` is (a)`(f_n(x)d)/(dx){f_(n-1)(x)}` (b) `f_n(x)f_(n-1)(x)` (c)`f_n(x)f_(n-1)(x).......f_2(x)dotf_1(x)` (d)none of these

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