" If "alpha,beta,gamma" are the roots of "x^(3)+2x^(2)-3x-1=0" then "alpha^(-2)+beta^(-2)+gamma^(-2)=

If alpha, beta, gamma are roots of x^(3) + 2x^(2) - 3x - 1 =0, then a^(-2)- beta^(-2) + gamma^(-2) =

If alpha, beta, gamma are the roots of x^(3) + x^(2) + x + 1 = 0 then alpha^(2) + beta^(2) + gamma^(2) =

If alpha,beta,gamma are the roots of the equation 2x^(3)x^(2)+x-1=0 then alpha^(2)+beta^(2)+gamma^(2)=

If alpha ,beta, gamma are the roots of 2x^(3)-2x-1=0 then (sum alpha beta)^(2)

If alpha,beta,gamma are the roots of x^(3)-2x^(2)+3x-4=0 then the value of alpha^(2)beta^(2)+beta^(2)gamma^(2)+gamma^(2)alpha^(2) is

If alpha,beta,gamma are the roots of x^(3)-3x^(2)+4x-7=0, then (alpha+2)(beta+2)(gamma+2)=

If alpha,beta,gamma are the roots of the equation 2x^(3)-3x^(2)+6x+1=0, then alpha^(2)+beta^(2)+gamma^(2) is equal to

If alpha,beta,gamma are the roots of x^(3)+2x^(2)+3x+8=0 then (alpha+beta)(beta+gamma)(gamma+alpha)=

If alpha , beta , gamma are the roots of x^3 +2x^2 +3x +8=0 then (3-alpha )(3 - beta) (3-gamma) =

If alpha , beta , gamma are the roots of x^3 +2x^2 +3x +8=0 then (3-alpha )(3 - beta) (3-gamma) =