[" The equations of the "],[" latusrecta of the hyperbola "],[3y^(2)-4x^(2)=12" are "]

The equation of the latusrectum of the hyperbola 3y^(2)-4x^(2)=12 are

The equation of the latusrectum of the hyperbola 3y^(2)-4x^(2)=12 are

Find the length of latus rectum and the equations of the directrices of the hyperbola 3y^(2) - 4x^(2) = 12

The equation of the latusrecta of the hyperola ((x-4)^(2))/(16)-((y-3)^(2))/(20)=1 are

The equation of the directrices of the hyperbola 3x^(2)-3y^(2)-18x+12y+2=0 is

The equation of the normal at theta=(pi)/(3) to the hyperbola 3x^(2)4y^(2)=12is

The equation of th directrices of the hyperbola 3x^(2)-3y^(2)-18x+12y+2=0 is

The eccentricity of the hyperbola 3x^(2)-4y^(2)=-12 is

The eccentricity of the hyperbola 3x^(2)-4y^(2)=-12 is

The equation of the normal at theta=(pi)/(6) to the hyperbola 3 x^(2)-4 y^(2)=12 is