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If (lim)(x->0)(sin(n x)[(a-n)n x-t a n x...

If `(lim)_(x->0)(sin(n x)[(a-n)n x-t a n x])/(x^2)=n (n >0)` then the value of `' a '` is equal to `1/n` b. `n^2+1` c. `(n^2+1)/n` d. none

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