When cold `NaOH` reacts with `Cl_(2)` which of the following is formed
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When dilute "NaOH" react with \(Cl_{2}\) the products formed are (A) NaCl+NaOCl (B)NaCl +\(NaClO_{3}\) (C) NaCl+\(H_{2}\)O (D) \(NaClO_{3}\)+\(H_{2}\)O
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When propanamide is reacted with Br_(2) and NaOH, the product formed is :
When propanamide is reacted with Br_(2) and NaOH, the product formed is :