In a double-slit experiment, the separation between the slits is `d=25` cm and the distance of the screen `D = 120` cm from the slits. If the wavelength of light used is `lamda = 6000 Å` and `I_(0)` is the intensity of the central bright fringe, what is the intensity at a distance `x=4.8 xx 10^(-5)`m from the central maximum ?

In a double slit experiment, the separation between the slits is d = 0.25 cm and the distance of the screen D = 100 cm from the slits. If the wavelength of light used is lambda = 6000 Å and I_(0) is the intensity of the central bright fringe, the intensity at a distance x =4xx10^(-5)m from the central maximum is

In a double slit experiment ,the separation between the slits is d=0.25cm and the distance of the screen D=100 cm from the slits .if the wavelength of light used in lambda=6000Å and I_(0) is the intensity of the central bright fringe. The intensity at a distance x=4xx10^(-5) in form the central maximum is-

In a double slit experiment ,the separation between the slits is d=0.25cm and the distance of the screen D=100 cm from the slits .if the wavelength of light used in lambda=6000Å and I_(0) is the intensity of the central bright fringe.the intensity at a distance x=4xx10^(-5) in form the central maximum is-

In a double slit experiment, the separation between the slits is d and distance of the screen from slits is D. If the wavelength of light used is lambda and I is theintensity of central bright fringe, then intensity at distance from central maximum is

In a double slit experiment the separation between the slits is d and distance of screen from slits is D. If the wavelenth of light used is lamda and I is the intensity of central bright fringe, then intensity at distance x from central maximum is given by

In Young's double - slit experiment, the distance between slits is d = 0.25 cm and the distance of the screen D = 120 cm from the slits. If the wavelength of light used is lambda=6000Å and I_(0) is the intensity of central maximum, then the minimum distance of the point from the centre, where the intensity is (I_(0))/(2) is kxx10^(-5)m . What is the value of k?

In Young's double - slit experiment, the distance between slits is d = 0.25 cm and the distance of the screen D = 120 cm from the slits. If the wavelength of light used is lambda=6000Å and I_(0) is the intensity of central maximum, then the minimum distance of the point from the centre, where the intensity is (I_(0))/(2) is kxx10^(-5)m . What is the value of k?

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is 6000Å . The width of the fringe on the screen is

In YDSE, the distance between the slits is 1 m m and screen is 25cm away from the slits . If the wavelength of light is 6000 Å , the fringe width on the secreen is