[0.1mol" of "CH_(3)NH_(2)" (ionisation constant,"Kb=5times10^(-4))" is mixed with "0.08molHCl" and the vol "],[1L" .Find the "[H^(+)]" of resulting solution."]

0.1mol of CH_(3)NH_(2) (K_(b) = 5 xx 10^(-4)) is mixed with 0.08mol of HCI and diluted to 1L . Which statement is correct?

0.1 mol of CH_(3)NH_(2)(K_(b)=5.0xx10^(-4)) is mixed with 0.08 mol of HCl and diluted to one litre. What will be the H^(+) ion concentration in the solution ?

0.1 mol of CH_(3)NH_(2)" "(K_(b)=5 times 10^(-4)" at "298K) is mixed withi 0.08 mol of HCl and the volume made upto 1 litre by adding water. The pH of the resulting solution is

0.1 mole of CH_(3)NH_(2) (K_(b)=5xx10^(-4)) is mixed with 0.08 mole of HCl and diluted to one litre. The [H^(+)] in solution is

0.1mol of RNH_(2)(K_(b) = 5 xx 10^(-4)) is mixed with 0.08mol of HC1 and diluted to 1L . Calculate the [H^(o+)] in the solution.