Suppose A, B are two points on `2x-y+3=0 and P(1,2)` is such that PA=PB. Then the mid point of AB is

Suppose A, B are two points on 2 x-y+3=0 and P(1,2) is such that P A=P B , then the mid point of A B is

If A and B are two points on the line joining P (2,5) and Q (4,-7) such that PA =AB=BQ then the mid point of seg AB is

A(-9, 0) and B(-1, 0) are two points. If P(x, y) is a point such that 3PB = PA , then the locus of P is

A(-9,0),B(-1,0) are two points.If P is a point such that PA:PB=3:1, then the locus of P is

A and B are two points on the x-axis and y-axis respectively. P(2, -3) is the mid point of AB. Find the equation of line AB.

A and B are two points on the x-axis and y-axis respectively. P(2, -3) is the mid point of AB. Find the slope of line AB

A and B are two points on the x-axis and y-axis respectively. P(2, -3) is the mid point of AB. Find the co-ordinates of A and B.

A(2, 1) and B(1, 2) are two points. If P is a point such that PA : PB = 2:1 , then the locus of P is