[25*(x+y)/(xy)=2],[(x-y)/(xy)=6]

Solve the following system of equations by method of cross-multiplication: (x+y)/(xy)=2,quad (x-y)/(xy)=6

Solve the following system of equations: (x+y)/(xy)=2,quad (x-y)/(xy)=6

Solve: (x+y)/(xy)=2 and (x-y)/(xy)=6

The value of y when (x+y)/(xy)=2" and "(x-y)/(xy)=6 is

(xy)/(x+y)=6/5 ; (xy)/(y-x)=6

(xy)/(x+y)=(6)/(5)(xy)/(y-x)=6

Solve by any method: (xy)/(x+y)=6/5, (xy)/(y-x)=6

Solve the simultaneous equations : (6x+3y)/(xy) = 6, (2x+4y)/(xy) = 5

(xy)/(x-y)=(1)/(2);(xy)/(x+y)=(1)/(5) wherex +y!=0;x-y!=0

The average of the reciprocals of x and y is (a) ((x+y))/((x-y)) (b) ((x+y))/(2xy) (c) (2(x+y))/(xy) (d) (2xy)/((x+y))