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4m + 3n = 18, 3m-2n = 5...

`4m + 3n = 18, 3m-2n = 5`

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If sin A + cos A = m and sin^3 A + cos^3A=n , then (1) m^3-3m + n = 0 (2) n^3-3n + 2m=0 (3) m^3-3m + 2n = 0 (4) m3 + 3m + 2n = 0

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If (4m + 3n)/(4m - 3n) = (7)/(4) use properties of proportion to find : (i) m : n (ii) (2m^(2) - 11n^(2))/(2m^(2) + 11n^(2)) .