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" (ii) "tan2x=(2tan x)/(1-tan^(2)x)...

" (ii) "tan2x=(2tan x)/(1-tan^(2)x)

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Statement -1: If 2"sin"2x - "cos" 2x=1, x ne (2n+1) (pi)/(2), n in Z, "then sin" 2x + "cos" 2x = 5 Statement-2: "sin"2x + "cos"2x = (1+2"tan" x - "tan"^(2)x)/(1+"tan"^(2)x)

Statement -1: If 2"sin"2x - "cos" 2x=1, x ne (2n+1) (pi)/(2), n in Z, "then sin" 2x + "cos" 2x = 5 Statement-2: "sin"2x + "cos"2x = (1+2"tan" x - "tan"^(2)x)/(1+"tan"^(2)x)

Statement -1: If 2"sin"2x - "cos" 2x=1, x ne (2n+1) (pi)/(2), n in Z, "then sin" 2x + "cos" 2x = 5 Statement-2: "sin"2x + "cos"2x = (1+2"tan" x - "tan"^(2)x)/(1+"tan"^(2)x)

Statement -1: If 2"sin"2x - "cos" 2x=1, x ne (2n+1) (pi)/(2), n in Z, "then sin" 2x + "cos" 2x = 5 Statement-2: "sin"2x + "cos"2x = (1+2"tan" x - "tan"^(2)x)/(1+"tan"^(2)x)

Statement -1: If 2"sin"2x - "cos" 2x=1, x ne (2n+1) (pi)/(2), n in Z, "then sin" 2x + "cos" 2x = 5 Statement-2: "sin"2x + "cos"2x = (1+2"tan" x - "tan"^(2)x)/(1+"tan"^(2)x)