" UA."x sec^(2)x

If int e^(sec x)(sec x tan x f(x)+(sec x tan x + sec^(2) x))dx = e^(sec x)f(x) + C , then a possible choice of f(x) is

If int e^(sec x)(sec x tan x f(x)+(sec x tan x + sec^(2) x))dx = e^(sec x)f(x) + C , then a possible choice of f(x) is

If int e^(sec x)(sec x tan x f(x)+(sec x tan x + sec^(2) x))dx = e^(sec x)f(x) + C , then a possible choice of f(x) is

If x ne 0 , then 1+ secx + sec^(2)x + sec^(3)x + sec^(4)x + sec^(5)x is equal to ………….

Integrate x sec^(2)x with respect to x.

If sec x + sec^(2) x = 1 then the value of tan^(8) x - tan^(4) x - 2 tan^(2) x +1 will be equal to 0

int e^(tan x) (sec^(2) x + sec^(3) x sin x ) dx is equal to

Least value of function f(x)=(2sec^(2)x+2sec x+1)/(sec^(2)x+sec x+5)is:

(sec x sec y + tan x tan y) ^ (2) - (sec x tan y + tan x sec y) ^ (2) = 1 Prove it

The solution of the differential equation cos y log(sec x+tan x)dx=cos x log(sec y+tan y)dy is (a) sec^(2)x+sec^(2)y=c(b)sec x+sec y=c(c)sec x-sec y=c(d)Non of these