10.x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)

The normal to the curve x=a(cos theta-theta sin theta),y=a(sin theta-theta cos theta) at any point,theta, is such that

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)

Show that the normal at any point theta to the curve x=a(cos theta+ theta sin theta), y=a( sin theta- theta cos theta) is at a constant distance from the origin.

If x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta), prove that (d^(2)x)/(dth eta^(2))=a(cos theta-theta sin theta),(d^(2)y)/(dth eta^(2))=a(sin theta+theta cos theta) and (d^(2)y)/(dx^(2))=(sec^(3)theta)/(a theta)

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that

The normal to the curve : x=a(cos theta+theta sin theta), y = a (sin theta-theta cos theta) at any point 'theta' is such that:

The normal to the curve : x=a(cos theta+theta sin theta), y = a (sin theta-theta cos theta) at any point 'theta' is such that: