|[a^(2)+2a,2a+1,1],[2a+1,a+2,1],[3,3,1]|=(a-1)^(3)

Evaluate the following: |[a^2+2a, 2a+1, 1],[2a+1, a+2, 1],[3,3,1]|

Prove that: |a^2+2a2a+1 1 2a+1a+2 1 3 3 1|=(a-1)^3 .

D=|{:(a^2+2a,2a+1,1),(2a+1,a+2,1),(3,3,1):}| then,

A=[[1,2,3],[3,-2,1],[4,2,1]] A^-1

If A=[[0 ,1 ,3],[ 1, 2,x],[2, 3, 1]] and A^(-1)=[[1//2,-4 ,5//2],[-1//2, 3,-3//2],[ 1//2,y,1//2]] ,find x ,\ y .

On set A={1,2,3}, relation R and S are given by R={(1,1),(2,2),(3,3),(1,2),(2,1)} and S={(1,1),(2,2),(3,3),(1,3),(3,1) Then

If A=[[0,1,3],[1,2,x],[2,3,1]] and A^(-1)=[[(1)/(2),-4,(5)/(2)],[-(1)/(2),3,-(3)/(2)],[(1)/(2),y,(1)/(2)]] . Find x,y

If A=[[0, 1,2],[1,2,3],[3,a,1]]and A^(-1)[[1//2,-1//2,1//2],[-4,3,b],[5//2,-3//2,1//2]] then

If A=[[0, 1,2],[1,2,3],[3,a,1]]and A^(-1)[[1//2,-1//2,1//2],[-4,3,b],[5//2,-3//2,1//2]] then